How To Parse The Xml Wrapping Json

Can Any one tell me How to parse the following [{'OSID':'2','PhoneVersion':'IPHONE5','PhoneOS':'IOS','ImageName':'t_3@2x.png','Image

Solution 1:

Thanks for all for the replies and make me understand what steps do I need to do this. Well I was asking about how to remove the xml tags when parsing xml well it was quite obvious that parsing xml is little more tricky as compare to json and yes from the tutorial I learnt how to parse it but was answerable how to parse this xml response which has no name space and no method name etc

So I am posting this as an answer if some one trap in the same case (specially when web designers/server side programmers putting it on you :( . )

I have used the following class to parse the xml with out name space and r returned me string. The code goes like as following

publicclassStringXmlParser {
// your xml doesn't have any name spacing so make it null.privatestaticfinalStringns=null;

public String parse(InputStream in)throws XmlPullParserException, IOException {
    try {
        XmlPullParserparser= Xml.newPullParser();
        parser.setFeature(XmlPullParser.FEATURE_PROCESS_NAMESPACES, false);
        parser.setInput(in,null);
        parser.nextTag();
        return readString(parser);
    } finally {
        in.close();
    }
}

private String readString(XmlPullParser parser)throws XmlPullParserException, IOException {
    parser.require(XmlPullParser.START_TAG, ns, "string");
    StringjsonString= readText(parser);
    parser.require(XmlPullParser.END_TAG, ns, "string");
    return jsonString;
}

private String readText(XmlPullParser parser)throws IOException, XmlPullParserException {
    Stringresult="";
    if (parser.next() == XmlPullParser.TEXT) {
        result = parser.getText();
        parser.nextTag();
    }
    return result;
}

}

This has solved my case. I hope if some one want the same solution then it may help him out. Just uploading the answer for the sole purpose of helping pure beginners.